What is log_{7}((\sqrt[3]{19})/(s^2r)) ?

The solution to log_{7}((\sqrt[3]{19})/(s^2r)) is log_{7}(\sqrt[3]{19})-2log_{7}(s)-log_{7}(r)

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simplify log_{7}((\sqrt[3]{19})/(s^2r))

simplify

Solution steps

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

Simplify

lo g_{7} (s^{2} r) : 2 lo g_{7} (s) + lo g_{7} (r)

Apply the distributive law:

- (a + b) = - a - b

- (2 lo g_{7} (s) + lo g_{7} (r)) = - 2 lo g_{7} (s) - lo g_{7} (r)

lo g_{8} (9 r)

77 ln (x) + 23 ln (1 - x) + 56.23

lo g_{3} (\frac{81}{x ^{2} + 5})

lo g_{7} (11) + lo g_{7} (3)

lo g_{10} (\frac{z ^{6}}{x})

What is log_{7}((\sqrt[3]{19})/(s^2r)) ?
The solution to log_{7}((\sqrt[3]{19})/(s^2r)) is log_{7}(\sqrt[3]{19})-2log_{7}(s)-log_{7}(r)