What is log_{10}(4^{-1})+log_{10}(1/2) ?

The solution to log_{10}(4^{-1})+log_{10}(1/2) is -3log_{10}(2)

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simplify log_{10}(4^{-1})+log_{10}(1/2)

simplify

lo g_{10} (4^{- 1}) + lo g_{10} (\frac{1}{2})

- 3 lo g_{10} (2)

Decimal Notation

- 0.90308 \dots

Solution steps

lo g_{10} (4^{- 1}) + lo g_{10} (\frac{1}{2})

lo g_{10} (4^{- 1}) = - 2 lo g_{10} (2)

lo g_{10} (\frac{1}{2}) = - lo g_{10} (2)

= - 2 lo g_{10} (2) - lo g_{10} (2)

Add similar elements:

- 2 lo g_{10} (2) - lo g_{10} (2) = - 3 lo g_{10} (2)

= - 3 lo g_{10} (2)

lo g_{10} (\frac{3 a ^{3}}{5 b})

ln (a e^{- a x})

\frac{1}{5} lo g_{b} (x^{6} y^{7}) - \frac{5}{7} lo g_{b} (x^{3} y)

lo g_{3} (x^{4} y)

lo g_{b} (\frac{p ^{2} q ^{5}}{m ^{4} b ^{9}})

What is log_{10}(4^{-1})+log_{10}(1/2) ?
The solution to log_{10}(4^{-1})+log_{10}(1/2) is -3log_{10}(2)