What is 2log_{3}(r)+log_{3}(s) ?

The solution to 2log_{3}(r)+log_{3}(s) is log_{3}(r^2s)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 2log_{3}(r)+log_{3}(s)

simplify

2 lo g_{3} (r) + lo g_{3} (s)

lo g_{3} (r^{2} s)

Solution steps

2 lo g_{3} (r) + lo g_{3} (s)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{3} (r) = lo g_{3} (r^{2})

= lo g_{3} (r^{2}) + lo g_{3} (s)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{3} (r^{2}) + lo g_{3} (s) = lo g_{3} (r^{2} s)

= lo g_{3} (r^{2} s)

- 10 ln (16) + 10 ln (9)

lo g_{3} (2 z) - lo g_{3} (x)

\frac{8}{12} lo g_{2} (\frac{8}{12}) + \frac{4}{12} lo g_{2} (\frac{4}{12})

lo g_{10} ((19 y)^{6})

lo g_{3} (27 (x^{2} - 49))

What is 2log_{3}(r)+log_{3}(s) ?
The solution to 2log_{3}(r)+log_{3}(s) is log_{3}(r^2s)