What is log_{7}((49m^6)/(k^3)) ?

The solution to log_{7}((49m^6)/(k^3)) is 2+6log_{7}(m)-3log_{7}(k)

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simplify log_{7}((49m^6)/(k^3))

simplify

lo g_{7} (\frac{49 m ^{6}}{k ^{3}})

2 + 6 lo g_{7} (m) - 3 lo g_{7} (k)

Solution steps

lo g_{7} (\frac{49 m ^{6}}{k ^{3}})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{7} (\frac{49 m ^{6}}{k ^{3}}) = lo g_{7} (49 m^{6}) - lo g_{7} (k^{3})

= lo g_{7} (49 m^{6}) - lo g_{7} (k^{3})

lo g_{7} (49 m^{6}) = 2 + 6 lo g_{7} (m)

lo g_{7} (k^{3}) = 3 lo g_{7} (k)

= 2 + 6 lo g_{7} (m) - 3 lo g_{7} (k)

3.79588 + lo g_{10} (\frac{0.2}{0.5})

lo g_{10} (2 c d)

3 (ln (x) - 2 ln (x^{2} + 1)) + 2 ln (5)

lo g_{8} (4) + 2 lo g_{8} (x)

ln (\frac{23}{7})

What is log_{7}((49m^6)/(k^3)) ?
The solution to log_{7}((49m^6)/(k^3)) is 2+6log_{7}(m)-3log_{7}(k)