What is log_{2}(x)+log_{2}(x-1) ?

The solution to log_{2}(x)+log_{2}(x-1) is log_{2}(x(x-1))

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simplify log_{2}(x)+log_{2}(x-1)

simplify

lo g_{2} (x) + lo g_{2} (x - 1)

lo g_{2} (x (x - 1))

Solution steps

lo g_{2} (x) + lo g_{2} (x - 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (x) + lo g_{2} (x - 1) = lo g_{2} (x (x - 1))

= lo g_{2} (x (x - 1))

\frac{1}{3} ln (x) + \frac{2}{3} ln (y)

lo g_{b} (\frac{A}{10})

2 ln (3) - 3 ln (3) + 2 ln (5)

2 ln (\frac{π}{3})

ln (\frac{w ^{5} x ^{\frac{4}{5}}}{y ^{8} z ^{7}})

What is log_{2}(x)+log_{2}(x-1) ?
The solution to log_{2}(x)+log_{2}(x-1) is log_{2}(x(x-1))