What is log_{7}(12)-log_{7}(2) ?

The solution to log_{7}(12)-log_{7}(2) is log_{7}(6)

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simplify log_{7}(12)-log_{7}(2)

simplify

lo g_{7} (12) - lo g_{7} (2)

lo g_{7} (6)

Decimal Notation

0.92078 \dots

Solution steps

lo g_{7} (12) - lo g_{7} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{7} (12) - lo g_{7} (2) = lo g_{7} (\frac{12}{2})

= lo g_{7} (\frac{12}{2})

Divide the numbers:

\frac{12}{2} = 6

= lo g_{7} (6)

lo g_{10} (x^{2} - 2 x - 15) - lo g_{10} (x + 3)

lo g_{3} (\frac{x}{27})

ln (- i e^{14})

\frac{8}{12} lo g_{10} (\frac{8}{12}) + \frac{4}{12} lo g_{10} (\frac{4}{12})

What is log_{7}(12)-log_{7}(2) ?
The solution to log_{7}(12)-log_{7}(2) is log_{7}(6)