What is ln((x^2-1)/(x^2+1)) ?

The solution to ln((x^2-1)/(x^2+1)) is ln(x^2-1)-ln(x^2+1)

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simplify ln((x^2-1)/(x^2+1))

simplify

ln (\frac{x ^{2} - 1}{x ^{2} + 1})

ln (x^{2} - 1) - ln (x^{2} + 1)

Solution steps

ln (\frac{x ^{2} - 1}{x ^{2} + 1})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{x ^{2} - 1}{x ^{2} + 1}) = ln (x^{2} - 1) - ln (x^{2} + 1)

= ln (x^{2} - 1) - ln (x^{2} + 1)

4 ln (x) + 3 ln (y) - 5 ln (z)

ln (\frac{( x + 1 )}{( 1 - x )})

8 ln (x) - \frac{1}{5} ln (y)

lo g_{A} (A \cdot 8^{4})

\frac{1}{3} lo g_{10} (125) - \frac{1}{2} lo g_{10} (64)

What is ln((x^2-1)/(x^2+1)) ?
The solution to ln((x^2-1)/(x^2+1)) is ln(x^2-1)-ln(x^2+1)