What is log_{10}(3x)+log_{10}(2x) ?

The solution to log_{10}(3x)+log_{10}(2x) is log_{10}(6x^2)

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simplify log_{10}(3x)+log_{10}(2x)

simplify

lo g_{10} (3 x) + lo g_{10} (2 x)

lo g_{10} (6 x^{2})

Solution steps

lo g_{10} (3 x) + lo g_{10} (2 x)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (3 x) + lo g_{10} (2 x) = lo g_{10} (3 x \cdot 2 x)

= lo g_{10} (3 x \cdot 2 x)

Simplify

3 x \cdot 2 x : 6 x^{2}

= lo g_{10} (6 x^{2})

lo g_{b} (x^{6} z)

ln (2) + 2 ln (3)

lo g_{10} (x^{6} y)

lo g_{10} (b) + 8 lo g_{10} (d)

2 ln (\frac{( 1000 + 10 t )}{1000})

What is log_{10}(3x)+log_{10}(2x) ?
The solution to log_{10}(3x)+log_{10}(2x) is log_{10}(6x^2)