What is log_{10}((rsqrt(7))/(s^2)) ?

The solution to log_{10}((rsqrt(7))/(s^2)) is log_{10}(r)+log_{10}(sqrt(7))-2log_{10}(s)

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simplify log_{10}((rsqrt(7))/(s^2))

simplify

lo g_{10} (\frac{r 7}{s ^{2}})

lo g_{10} (r) + lo g_{10} (7) - 2 lo g_{10} (s)

Solution steps

lo g_{10} (\frac{r 7}{s ^{2}})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{r 7}{s ^{2}}) = lo g_{10} (r 7) - lo g_{10} (s^{2})

= lo g_{10} (r 7) - lo g_{10} (s^{2})

lo g_{10} (r 7) = lo g_{10} (r) + lo g_{10} (7)

lo g_{10} (s^{2}) = 2 lo g_{10} (s)

= lo g_{10} (r) + lo g_{10} (7) - 2 lo g_{10} (s)

\frac{π + 2}{2} ln (\frac{π}{4})

ln (3) - ln (- 1)

lo g_{e} (\frac{20000}{7165}) \cdot 12

\frac{2 ln ( - 1 ) - ln ^{2} ( - 1 )}{- 1 ^{2}}

231.84357 - 224.62838 - 8.314 ln (\frac{1}{5.2})

What is log_{10}((rsqrt(7))/(s^2)) ?
The solution to log_{10}((rsqrt(7))/(s^2)) is log_{10}(r)+log_{10}(sqrt(7))-2log_{10}(s)