What is 2log_{10}(x)-log_{10}(y) ?

The solution to 2log_{10}(x)-log_{10}(y) is log_{10}((x^2)/y)

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simplify 2log_{10}(x)-log_{10}(y)

simplify

2 lo g_{10} (x) - lo g_{10} (y)

lo g_{10} (\frac{x ^{2}}{y})

Solution steps

2 lo g_{10} (x) - lo g_{10} (y)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= lo g_{10} (x^{2}) - lo g_{10} (y)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (x^{2}) - lo g_{10} (y) = lo g_{10} (\frac{x ^{2}}{y})

= lo g_{10} (\frac{x ^{2}}{y})

lo g_{2} (\frac{s ^{7}}{5 t ^{2}})

ln (\frac{m ^{3}}{n ^{7}})

lo g_{10} (\frac{9 a ^{16}}{b ^{2}})

4 - lo g_{4} (16 y)

lo g_{10} (x^{2} + 2 x - 48) - lo g_{10} (x^{2} - 64)

What is 2log_{10}(x)-log_{10}(y) ?
The solution to 2log_{10}(x)-log_{10}(y) is log_{10}((x^2)/y)