What is log_{2}(x)+log_{2}(x+15)+log_{2}(16) ?

The solution to log_{2}(x)+log_{2}(x+15)+log_{2}(16) is log_{2}(x(x+15))+4

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simplify log_{2}(x)+log_{2}(x+15)+log_{2}(16)

simplify

lo g_{2} (x) + lo g_{2} (x + 15) + lo g_{2} (16)

lo g_{2} (x (x + 15)) + 4

Solution steps

lo g_{2} (x) + lo g_{2} (x + 15) + lo g_{2} (16)

lo g_{2} (16) = 4

= lo g_{2} (x) + lo g_{2} (x + 15) + 4

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (x) + lo g_{2} (x + 15) = lo g_{2} (x (x + 15))

= lo g_{2} (x (x + 15)) + 4

2 lo g_{3} (6) - lo g_{3} (8)

lo g_{4} (\frac{x ^{2}}{y ^{6}})

lo g_{a} (\frac{1}{64})

- lo g_{10} (5 \cdot 1 0^{- 6})

What is log_{2}(x)+log_{2}(x+15)+log_{2}(16) ?
The solution to log_{2}(x)+log_{2}(x+15)+log_{2}(16) is log_{2}(x(x+15))+4