What is 1/3 (log_{8}(a)+2log_{8}(b)) ?

The solution to 1/3 (log_{8}(a)+2log_{8}(b)) is (log_{8}(a)+2log_{8}(b))/3

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simplify 1/3 (log_{8}(a)+2log_{8}(b))

simplify

\frac{1}{3} (lo g_{8} (a) + 2 lo g_{8} (b))

\frac{lo g _{8} ( a ) + 2 lo g _{8} ( b )}{3}

Solution steps

\frac{1}{3} (lo g_{8} (a) + 2 lo g_{8} (b))

Apply the distributive law:

a (b + c) = ab + a c

\frac{1}{3} (lo g_{8} (a) + 2 lo g_{8} (b)) = \frac{1}{3} lo g_{8} (a) + \frac{1}{3} \cdot 2 lo g_{8} (b)

= \frac{1}{3} lo g_{8} (a) + \frac{1}{3} \cdot 2 lo g_{8} (b)

Simplify

\frac{1}{3} lo g_{8} (a) + \frac{1}{3} \cdot 2 lo g_{8} (b) : \frac{lo g _{8} ( a ) + 2 lo g _{8} ( b )}{3}

= \frac{lo g _{8} ( a ) + 2 lo g _{8} ( b )}{3}

ln (\frac{( 1.6 \cdot 1 0 ^{- 19} )}{( 6.48 \cdot 1 0 ^{- 5} )})

lo g_{10} (2) + \frac{1}{2} \cdot lo g_{10} (15) - \frac{1}{4} \cdot lo g_{10} (9)

lo g_{b} (x^{7} y^{3} z)

- 2 ln ∣ 4 - 1 ∣ + 3 ln ∣ 4 - 2 ∣ + ln 4^{2} + 1 + 2 - ln (\frac{5}{2})

lo g_{2} (5) + lo g_{2} (x^{3})

What is 1/3 (log_{8}(a)+2log_{8}(b)) ?
The solution to 1/3 (log_{8}(a)+2log_{8}(b)) is (log_{8}(a)+2log_{8}(b))/3