What is log_{10}(x)-log_{10}(x+1) ?

The solution to log_{10}(x)-log_{10}(x+1) is log_{10}(x/(x+1))

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simplify log_{10}(x)-log_{10}(x+1)

simplify

lo g_{10} (x) - lo g_{10} (x + 1)

lo g_{10} (\frac{x}{x + 1})

Solution steps

lo g_{10} (x) - lo g_{10} (x + 1)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x) - lo g_{10} (x + 1) = lo g_{10} (\frac{x}{x + 1})

= lo g_{10} (\frac{x}{x + 1})

lo g_{2} (x^{2}) - 3 lo g_{2} (x) - 28

2 (ln ∣ a + 2 ∣ - ln ∣ a ∣)

- ln (2 π)

lo g_{7} (3) - lo g_{7} (5)

lo g_{2} (x) + lo g_{2} (5)

What is log_{10}(x)-log_{10}(x+1) ?
The solution to log_{10}(x)-log_{10}(x+1) is log_{10}(x/(x+1))