What is log_{8}(16x)+log_{8}(2x^2) ?

The solution to log_{8}(16x)+log_{8}(2x^2) is log_{8}(32x^3)

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simplify log_{8}(16x)+log_{8}(2x^2)

simplify

lo g_{8} (16 x) + lo g_{8} (2 x^{2})

lo g_{8} (32 x^{3})

Solution steps

lo g_{8} (16 x) + lo g_{8} (2 x^{2})

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{8} (16 x) + lo g_{8} (2 x^{2}) = lo g_{8} (16 x \cdot 2 x^{2})

= lo g_{8} (16 x \cdot 2 x^{2})

Simplify

16 x \cdot 2 x^{2} : 32 x^{3}

= lo g_{8} (32 x^{3})

lo g_{10} (y x^{4})

2 \cdot lo g_{3} (x) + 3 \cdot lo g_{3} (2 y)

f (x) = ln (x^{9}) - ln (x)

ln (\frac{1}{e})

lo g_{3} (\frac{x ^{5} y}{w ^{3} z})

What is log_{8}(16x)+log_{8}(2x^2) ?
The solution to log_{8}(16x)+log_{8}(2x^2) is log_{8}(32x^3)