What is log_{10}(2)-log_{10}(1.035) ?

The solution to log_{10}(2)-log_{10}(1.035) is log_{10}(1.93236…)

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simplify log_{10}(2)-log_{10}(1.035)

simplify

lo g_{10} (2) - lo g_{10} (1.035)

lo g_{10} (1.93236 \dots)

Decimal Notation

0.28608 \dots

Solution steps

lo g_{10} (2) - lo g_{10} (1.035)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (2) - lo g_{10} (1.035) = lo g_{10} (\frac{2}{1.035})

= lo g_{10} (\frac{2}{1.035})

Divide the numbers:

\frac{2}{1.035} = 1.93236 \dots

= lo g_{10} (1.93236 \dots)

\frac{1}{2} lo g_{c} (x) + 3 lo g_{c} (y) - 5 lo g_{c} (x)

- 2 - lo g_{4} (z) - lo g_{4} (x^{3} - 27)

lo g_{10} (- 3 i)

lo g_{10} (x y^{9})

lo g_{4} (20) + lo g_{4} (5)

What is log_{10}(2)-log_{10}(1.035) ?
The solution to log_{10}(2)-log_{10}(1.035) is log_{10}(1.93236…)