What is 1.1-(0.0257)/2*ln((3.5)/(10^{-5)}) ?

The solution to 1.1-(0.0257)/2*ln((3.5)/(10^{-5)}) is 1.1-(0.0257)/2 (ln(3.5)--5ln(10))

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simplify 1.1-(0.0257)/2*ln((3.5)/(10^{-5)})

simplify

1.1 - \frac{0.0257}{2} \cdot ln (\frac{3.5}{1 0 ^{- 5}})

1.1 - \frac{0.0257}{2} (ln (3.5) - - 5 ln (10))

Decimal Notation

1.23184 \dots

Solution steps

1.1 - \frac{0.0257}{2} ln (\frac{3.5}{1 0 ^{- 5}})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{3.5}{1 0 ^{- 5}}) = ln (3.5) - ln (1 0^{- 5})

= 1.1 - \frac{0.0257}{2} (ln (3.5) - ln (1 0^{- 5}))

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (1 0^{- 5}) = - 5 ln (10)

= 1.1 - \frac{0.0257}{2} (ln (3.5) - - 5 ln (10))

lo g_{5} (\frac{f}{125})

lo g_{6} (\frac{2}{9 z})

\frac{1}{2} ln (x) + \frac{1}{2} ln (y)

lo g_{10} (14) + \frac{1}{2} lo g_{10} (3) - lo g_{10} (2)

What is 1.1-(0.0257)/2*ln((3.5)/(10^{-5)}) ?
The solution to 1.1-(0.0257)/2*ln((3.5)/(10^{-5)}) is 1.1-(0.0257)/2 (ln(3.5)--5ln(10))