What is ((0.05916)/4)ln(1.28*10^{83}) ?

The solution to ((0.05916)/4)ln(1.28*10^{83}) is (0.05916)/4 ln(1.28)+(4.91028)/4 ln(10)

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simplify ((0.05916)/4)ln(1.28*10^{83})

simplify

(\frac{0.05916}{4}) ln (1.28 \cdot 1 0^{83})

\frac{0.05916}{4} ln (1.28) + \frac{4.91028}{4} ln (10)

Decimal Notation

2.83023 \dots

Solution steps

(\frac{0.05916}{4}) ln (1.28 \cdot 1 0^{83})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

(\frac{0.05916}{4}) ln (1.28 \cdot 1 0^{83}) = (\frac{0.05916}{4}) ln (1.28) + (\frac{0.05916}{4}) ln (1 0^{83})

= (\frac{0.05916}{4}) ln (1.28) + (\frac{0.05916}{4}) ln (1 0^{83})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

ln (1 0^{83}) = 83 ln (10)

= \frac{0.05916}{4} ln (1.28) + \frac{0.05916}{4} \cdot 83 ln (10)

\frac{0.05916}{4} \cdot 83 ln (10) = \frac{4.91028}{4} ln (10)

= \frac{0.05916}{4} ln (1.28) + \frac{4.91028}{4} ln (10)

lo g_{c} (x^{2} y^{2} z)

5 ln (2) - \frac{1}{2} + 5 ln (3)

lo g_{4} (\frac{x ^{2}}{yz})

ln (a \cdot b^{x})

ln (\frac{4}{1.213})

What is ((0.05916)/4)ln(1.28*10^{83}) ?
The solution to ((0.05916)/4)ln(1.28*10^{83}) is (0.05916)/4 ln(1.28)+(4.91028)/4 ln(10)