What is 3*log_{10}(2)+log_{10}(x-4) ?

The solution to 3*log_{10}(2)+log_{10}(x-4) is log_{10}(8(x-4))

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simplify 3*log_{10}(2)+log_{10}(x-4)

simplify

3 \cdot lo g_{10} (2) + lo g_{10} (x - 4)

lo g_{10} (8 (x - 4))

Solution steps

3 lo g_{10} (2) + lo g_{10} (x - 4)

Apply log rule:

b \cdot lo g_{a} (x) = lo g_{a} (x^{b})

3 lo g_{10} (2) = lo g_{10} (2^{3})

= lo g_{10} (2^{3}) + lo g_{10} (x - 4)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (2^{3}) + lo g_{10} (x - 4) = lo g_{10} (2^{3} (x - 4))

= lo g_{10} (2^{3} (x - 4))

2^{3} = 8

= lo g_{10} (8 (x - 4))

\frac{( ln ( 300 ) - ln ( 700 ) )}{20}

ln (\frac{- 1}{- 5})

lo g_{2} (3) - lo g_{2} (7)

4 - lo g_{6} (36 y)

\frac{4}{3} ln (\frac{1}{0.03})

What is 3*log_{10}(2)+log_{10}(x-4) ?
The solution to 3*log_{10}(2)+log_{10}(x-4) is log_{10}(8(x-4))