What is ((ln(2))/2 t)-ln(-7t) ?

The solution to ((ln(2))/2 t)-ln(-7t) is (ln(2)t)/2-ln(7)-ln(t)

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simplify ((ln(2))/2 t)-ln(-7t)

simplify

(\frac{ln ( 2 )}{2} t) - ln (- 7 t)

\frac{ln ( 2 ) t}{2} - ln (7) - ln (t)

Solution steps

(\frac{ln ( 2 )}{2} t) - ln (- 7 t)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (- 7 t) = ln (7) + ln (t)

= (\frac{ln ( 2 )}{2} t) - (ln (t) + ln (7))

Remove parentheses:

(a) = a

= \frac{ln ( 2 )}{2} t - (ln (7) + ln (t))

Multiply

\frac{ln ( 2 )}{2} t : \frac{ln ( 2 ) t}{2}

= \frac{ln ( 2 ) t}{2} - (ln (t) + ln (7))

- (ln (7) + ln (t)) : - ln (7) - ln (t)

= \frac{ln ( 2 ) t}{2} - ln (7) - ln (t)

lo g_{5} (3) + lo g_{5} (4)

ln ∣ ln (4) ∣ - ln ∣ ln (2) ∣

ln (5) + 4 ln (x + 4) + 4 ln (x^{2} + 4)

1 - ln (3 x)

lo g_{10} (\frac{x + 1}{x - 1}) - 3

What is ((ln(2))/2 t)-ln(-7t) ?
The solution to ((ln(2))/2 t)-ln(-7t) is (ln(2)t)/2-ln(7)-ln(t)