What is 7log_{b}(v)+4log_{b}(x) ?

The solution to 7log_{b}(v)+4log_{b}(x) is log_{b}(v^7x^4)

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simplify 7log_{b}(v)+4log_{b}(x)

simplify

7 lo g_{b} (v) + 4 lo g_{b} (x)

lo g_{b} (v^{7} x^{4})

Solution steps

7 lo g_{b} (v) + 4 lo g_{b} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

7 lo g_{b} (v) = lo g_{b} (v^{7})

= lo g_{b} (v^{7}) + 4 lo g_{b} (x)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

4 lo g_{b} (x) = lo g_{b} (x^{4})

= lo g_{b} (v^{7}) + lo g_{b} (x^{4})

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{b} (v^{7}) + lo g_{b} (x^{4}) = lo g_{b} (v^{7} x^{4})

= lo g_{b} (v^{7} x^{4})

ln (- 2 ln (x))

lo g_{10} (\frac{2 x}{3})

lo g_{10} (2 x - 3) + \frac{1}{3} ln (27 x)

\frac{ln ^{2} ( 6 x ) - ln ^{2} ( 3 x ) + 2 ln ( 2 )}{2}

What is 7log_{b}(v)+4log_{b}(x) ?
The solution to 7log_{b}(v)+4log_{b}(x) is log_{b}(v^7x^4)