What is 3log_{10}(d)-log_{10}(k) ?

The solution to 3log_{10}(d)-log_{10}(k) is log_{10}((d^3)/k)

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simplify 3log_{10}(d)-log_{10}(k)

simplify

3 lo g_{10} (d) - lo g_{10} (k)

lo g_{10} (\frac{d ^{3}}{k})

Solution steps

3 lo g_{10} (d) - lo g_{10} (k)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

3 lo g_{10} (d) = lo g_{10} (d^{3})

= lo g_{10} (d^{3}) - lo g_{10} (k)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

lo g_{10} (d^{3}) - lo g_{10} (k) = lo g_{10} (\frac{d ^{3}}{k})

= lo g_{10} (\frac{d ^{3}}{k})

lo g_{4} (u^{3} v^{6})

lo g_{10} (\frac{2 x}{7})

3 lo g_{10} (x) + 6 lo g_{10} (x + 8)

(1) ln (\frac{1100}{1400}) - 0.287 ln (\frac{5}{20})

ln (\frac{a ^{x} + b ^{x} + c ^{x}}{3})

What is 3log_{10}(d)-log_{10}(k) ?
The solution to 3log_{10}(d)-log_{10}(k) is log_{10}((d^3)/k)