What is expand log_{8}((8x^2)/y) ?

The solution to expand log_{8}((8x^2)/y) is 1+2log_{8}(x)-log_{8}(y)

Popular >

expand log_{8}((8x^2)/y)

expand

lo g_{8} (\frac{8 x ^{2}}{y})

1 + 2 lo g_{8} (x) - lo g_{8} (y)

Solution steps

lo g_{8} (\frac{8 x ^{2}}{y})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

lo g_{8} (\frac{8 x ^{2}}{y}) = lo g_{8} (8 x^{2}) - lo g_{8} (y)

= lo g_{8} (8 x^{2}) - lo g_{8} (y)

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{8} (8 x^{2}) = lo g_{8} (8) + lo g_{8} (x^{2})

= lo g_{8} (8) + lo g_{8} (x^{2}) - lo g_{8} (y)

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{8} (x^{2}) = 2 lo g_{8} (x)

= lo g_{8} (8) + 2 lo g_{8} (x) - lo g_{8} (y)

Apply log rule:

lo g_{a} (a) = 1

= 1 + 2 lo g_{8} (x) - lo g_{8} (y)

\frac{ln ( 5 )}{ln ( 5 ) - 2 ln ( 3 )}

lo g_{10} (\frac{y ^{5}}{x ^{5} z})

lo g_{2} (x + 6) + lo g_{2} (x)

3 lo g_{10} (x) - 6 lo g_{10} (y)

ln (11) + 6 ln (x) + 6 ln (y)

What is expand log_{8}((8x^2)/y) ?
The solution to expand log_{8}((8x^2)/y) is 1+2log_{8}(x)-log_{8}(y)