What is log_{10}(x-2)+log_{10}(x+1) ?

The solution to log_{10}(x-2)+log_{10}(x+1) is log_{10}((x-2)(x+1))

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simplify log_{10}(x-2)+log_{10}(x+1)

simplify

lo g_{10} (x - 2) + lo g_{10} (x + 1)

lo g_{10} ((x - 2) (x + 1))

Solution steps

lo g_{10} (x - 2) + lo g_{10} (x + 1)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (x - 2) + lo g_{10} (x + 1) = lo g_{10} ((x - 2) (x + 1))

= lo g_{10} ((x - 2) (x + 1))

lo g_{10} (\frac{4 x}{5})

lo g_{3} (5) + lo g_{3} (10)

ln (\frac{e ^{9}}{5})

lo g_{3} (6 c) + lo g_{3} (\frac{1}{12})

- \frac{1}{45} ln (\frac{18 - ( - 7 )}{22 - ( - 7 )})

What is log_{10}(x-2)+log_{10}(x+1) ?
The solution to log_{10}(x-2)+log_{10}(x+1) is log_{10}((x-2)(x+1))