What is log_{b}(2)+log_{b}(3)+log_{b}(5) ?

The solution to log_{b}(2)+log_{b}(3)+log_{b}(5) is log_{b}(30)

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simplify log_{b}(2)+log_{b}(3)+log_{b}(5)

simplify

lo g_{b} (2) + lo g_{b} (3) + lo g_{b} (5)

lo g_{b} (30)

Solution steps

lo g_{b} (2) + lo g_{b} (3) + lo g_{b} (5)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (2) + lo g_{b} (3) = lo g_{b} (2 \cdot 3)

= lo g_{b} (2 \cdot 3) + lo g_{b} (5)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{b} (2 \cdot 3) + lo g_{b} (5) = lo g_{b} (2 \cdot 3 \cdot 5)

= lo g_{b} (2 \cdot 3 \cdot 5)

Multiply the numbers:

2 \cdot 3 \cdot 5 = 30

= lo g_{b} (30)

ln (\frac{4}{3}) \cdot ln (\frac{4}{3})

ln (x + 4) + ln (x) + ln (x + 10)

ln (\frac{50.14}{161.2})

lo g_{10} (\frac{B}{10 A})

What is log_{b}(2)+log_{b}(3)+log_{b}(5) ?
The solution to log_{b}(2)+log_{b}(3)+log_{b}(5) is log_{b}(30)