What is 20*log_{10}(4*3.1415*x*(8.16)) ?

The solution to 20*log_{10}(4*3.1415*x*(8.16)) is 20log_{10}(10253856)+20log_{10}(x)-100

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify 20log_{10}(43.1415x(8.16))

simplify

20 \cdot lo g_{10} (4 \cdot 3.1415 \cdot x \cdot (8.16))

20 lo g_{10} (10253856) + 20 lo g_{10} (x) - 100

Solution steps

20 lo g_{10} (4 \cdot 3.1415 x (8.16))

Apply rule:

(a) = a

(8.16) = 8.16

= 20 lo g_{10} (4 \cdot 3.1415 x \cdot 8.16)

Simplify

lo g_{10} (4 \cdot 3.1415 x \cdot 8.16) : lo g_{10} (10253856 x) - 5

= 20 (lo g_{10} (10253856 x) - 5)

Simplify

20 (lo g_{10} (10253856 x) - 5) : 20 lo g_{10} (10253856) + 20 lo g_{10} (x) - 100

= 20 lo g_{10} (10253856) + 20 lo g_{10} (x) - 100

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

20 lo g_{10} (10253856) = lo g_{10} (1025385 6^{20})

= lo g_{10} (1025385 6^{20}) + 20 lo g_{10} (x) - 100

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

20 lo g_{10} (x) = lo g_{10} (x^{20})

= lo g_{10} (1025385 6^{20}) + lo g_{10} (x^{20}) - 100

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (1025385 6^{20}) + lo g_{10} (x^{20}) = lo g_{10} (1025385 6^{20} x^{20})

= lo g_{10} (1025385 6^{20} x^{20}) - 100

Simplify

lo g_{10} (1025385 6^{20} x^{20}) : 20 lo g_{10} (10253856) + 20 lo g_{10} (x)

= 20 lo g_{10} (10253856) + 20 lo g_{10} (x) - 100

lo g_{2} (3 a)

ln (\frac{1}{b - a})

3 lo g_{10} (2) - lo g_{10} (5)

ln (\frac{- 4.1 + 8.05}{31.8})

lo g_{10} (1000 x^{4})

What is 20*log_{10}(4*3.1415*x*(8.16)) ?
The solution to 20*log_{10}(4*3.1415*x*(8.16)) is 20log_{10}(10253856)+20log_{10}(x)-100