What is log_{10}(((y^2))/(2z)) ?

The solution to log_{10}(((y^2))/(2z)) is 2log_{10}(y)-log_{10}(2)-log_{10}(z)

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simplify log_{10}(((y^2))/(2z))

simplify

lo g_{10} (\frac{( y ^{2} )}{2 z})

2 lo g_{10} (y) - lo g_{10} (2) - lo g_{10} (z)

Solution steps

lo g_{10} (\frac{y ^{2}}{2 z})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{y ^{2}}{2 z}) = lo g_{10} (y^{2}) - lo g_{10} (2 z)

= lo g_{10} (y^{2}) - lo g_{10} (2 z)

lo g_{10} (y^{2}) = 2 lo g_{10} (y)

lo g_{10} (2 z) = lo g_{10} (2) + lo g_{10} (z)

= 2 lo g_{10} (y) - (lo g_{10} (2) + lo g_{10} (z))

Apply the distributive law:

- (a + b) = - a - b

- (lo g_{10} (2) + lo g_{10} (z)) = - lo g_{10} (2) - lo g_{10} (z)

= 2 lo g_{10} (y) - lo g_{10} (2) - lo g_{10} (z)

lo g_{6} (\frac{f}{36})

ln (\frac{x ^{4} + 1}{x + 1})

3.8 + lo g_{10} (\frac{0.2}{0.5})

11 ln (x - 4) - 2 ln (x)

ln (x) + ln (13 y)

What is log_{10}(((y^2))/(2z)) ?
The solution to log_{10}(((y^2))/(2z)) is 2log_{10}(y)-log_{10}(2)-log_{10}(z)