What are the solutions to the equation x^2+4x+4=8 ?

The solutions to the equation x^2+4x+4=8 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

Find the zeros of x^2+4x+4=8

The zeros of x^2+4x+4=8 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))

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x^{2} + 4 x + 4 = 8

x = 2 (2 - 1), x = - 2 (1 + 2)

Decimal

x = 0.82842 \dots, x = - 4.82842 \dots

Solution steps

x^{2} + 4 x + 4 = 8

Move

8

to the left side

x^{2} + 4 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 4) = 42

x_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 2}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 2}{2 \cdot 1}

x = \frac{- 4 + 4 2}{2 \cdot 1} : 2 (2 - 1)

x = \frac{- 4 - 4 2}{2 \cdot 1} : - 2 (1 + 2)

The solutions to the quadratic equation are:

x = 2 (2 - 1), x = - 2 (1 + 2)

x y - 3 x^{3} y - 4 x y^{2} + 3 x^{2} + 7 x^{3} y

- 6 b - 6

6 \frac{729}{64}

- 1011 - 1111

\frac{1}{8} - 1

What are the solutions to the equation x^2+4x+4=8 ?
The solutions to the equation x^2+4x+4=8 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))
Find the zeros of x^2+4x+4=8
The zeros of x^2+4x+4=8 are x=2(sqrt(2)-1),x=-2(1+sqrt(2))