What is ln^2(e^2+2-2)+1/2-ln^2(-1) ?

The solution to ln^2(e^2+2-2)+1/2-ln^2(-1) is ln^2(-e^2)+1/2

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simplify ln^2(e^2+2-2)+1/2-ln^2(-1)

simplify

ln^{2} (e^{2} + 2 - 2) + \frac{1}{2} - ln^{2} (- 1)

ln^{2} (- e^{2}) + \frac{1}{2}

Decimal Notation

4.5

Solution steps

ln^{2} (e^{2} + 2 - 2) + \frac{1}{2} - ln^{2} (- 1)

Apply log rule:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln^{2} (e^{2} + 2 - 2) - ln^{2} (- 1) = ln^{2} (\frac{e ^{2} + 2 - 2}{- 1})

= ln^{2} (\frac{e ^{2} + 2 - 2}{- 1}) + \frac{1}{2}

\frac{e ^{2} + 2 - 2}{- 1} = - e^{2}

= ln^{2} (- e^{2}) + \frac{1}{2}

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What is ln^2(e^2+2-2)+1/2-ln^2(-1) ?
The solution to ln^2(e^2+2-2)+1/2-ln^2(-1) is ln^2(-e^2)+1/2