What are the solutions to the equation 9x+x^2+20=0 ?

The solutions to the equation 9x+x^2+20=0 are x=-4,x=-5

Find the zeros of 9x+x^2+20=0

The zeros of 9x+x^2+20=0 are x=-4,x=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x + x^{2} + 20 = 0

x = - 4, x = - 5

Solution steps

9 x + x^{2} + 20 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- 9 \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 1}{2 \cdot 1}, x_{2} = \frac{- 9 - 1}{2 \cdot 1}

x = \frac{- 9 + 1}{2 \cdot 1} : - 4

x = \frac{- 9 - 1}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = - 4, x = - 5

(x^{3} + 8)^{3}

4 z^{2} + 4 z - 3

- 6 < 2 x + 1 < 5

12 x^{3} + 8 x^{2} - 3 x - 2 \leq 0

\frac{2}{2} + \frac{1}{2}

What are the solutions to the equation 9x+x^2+20=0 ?
The solutions to the equation 9x+x^2+20=0 are x=-4,x=-5
Find the zeros of 9x+x^2+20=0
The zeros of 9x+x^2+20=0 are x=-4,x=-5