What is log_{10}(3)-log_{10}(6)-log_{10}(5) ?

The solution to log_{10}(3)-log_{10}(6)-log_{10}(5) is -1

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simplify log_{10}(3)-log_{10}(6)-log_{10}(5)

simplify

lo g_{10} (3) - lo g_{10} (6) - lo g_{10} (5)

- 1

Solution steps

lo g_{10} (3) - lo g_{10} (6) - lo g_{10} (5)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (3) - lo g_{10} (6) = lo g_{10} (\frac{3}{6})

= lo g_{10} (\frac{3}{6}) - lo g_{10} (5)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (\frac{3}{6}) - lo g_{10} (5) = lo g_{10} (\frac{\frac{3}{6}}{5})

= lo g_{10} (\frac{\frac{3}{6}}{5})

\frac{\frac{3}{6}}{5} = 1 0^{- 1}

= lo g_{10} (1 0^{- 1})

Apply log rule:

lo g_{a} (a^{b}) = b

= - 1

9 ln (x) - \frac{1}{3} ln (y)

lo g_{b} (\frac{p ^{4} q ^{6}}{m ^{4} b ^{9}})

lo g_{10} (\frac{10}{x ^{2} y})

(\frac{1}{2})^{3} - 24 ln (\frac{1}{2}) + 8

(\frac{1}{2})^{3} - 24 ln (\frac{1}{2}) + 3

What is log_{10}(3)-log_{10}(6)-log_{10}(5) ?
The solution to log_{10}(3)-log_{10}(6)-log_{10}(5) is -1