What is log_{2}((5y)/7) ?

The solution to log_{2}((5y)/7) is log_{2}(5)+log_{2}(y)-log_{2}(7)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{2}((5y)/7)

simplify

lo g_{2} (\frac{5 y}{7})

lo g_{2} (5) + lo g_{2} (y) - lo g_{2} (7)

Solution steps

lo g_{2} (\frac{5 y}{7})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{2} (\frac{5 y}{7}) = lo g_{2} (5 y) - lo g_{2} (7)

= lo g_{2} (5 y) - lo g_{2} (7)

Simplify

lo g_{2} (5 y) : lo g_{2} (5) + lo g_{2} (y)

= lo g_{2} (5) + lo g_{2} (y) - lo g_{2} (7)

lo g_{10} (6) 6

lo g_{3} (\frac{x ^{14}}{x - 2})

ln (\frac{( x ^{3} - 1 ) ^{2}}{( x + 3 ) ^{3}})

\frac{1}{2} ln (11)

lo g_{7} (\frac{f}{12})

What is log_{2}((5y)/7) ?
The solution to log_{2}((5y)/7) is log_{2}(5)+log_{2}(y)-log_{2}(7)