What is log_{b}(m)-log_{b}(n) ?

The solution to log_{b}(m)-log_{b}(n) is log_{b}(m/n)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{b}(m)-log_{b}(n)

simplify

lo g_{b} (m) - lo g_{b} (n)

lo g_{b} (\frac{m}{n})

Solution steps

lo g_{b} (m) - lo g_{b} (n)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{b} (m) - lo g_{b} (n) = lo g_{b} (\frac{m}{n})

= lo g_{b} (\frac{m}{n})

lo g_{6} ((u^{2} v)^{4})

lo g_{6} (18 x)

ln (\frac{e ^{4}}{13})

lo g_{5} (a^{4} b^{2})

\frac{7 ln ( 7 ) + 4 ln ( 2 )}{ln ( 7 ) - 2 ln ( 2 )}

What is log_{b}(m)-log_{b}(n) ?
The solution to log_{b}(m)-log_{b}(n) is log_{b}(m/n)