What is ln((2x-5)/(cos^2(3x))) ?

The solution to ln((2x-5)/(cos^2(3x))) is ln(2x-5)-ln(cos^2(3x))

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simplify ln((2x-5)/(cos^2(3x)))

simplify

ln (\frac{2 x - 5}{cos ^{2} ( 3 x )})

ln (2 x - 5) - ln (cos^{2} (3 x))

Solution steps

ln (\frac{2 x - 5}{cos ^{2} ( 3 x )})

Apply log rule:

lo g_{c} (\frac{a}{b}) = lo g_{c} (a) - lo g_{c} (b)

ln (\frac{2 x - 5}{cos ^{2} ( 3 x )}) = ln (2 x - 5) - ln (cos^{2} (3 x))

= ln (2 x - 5) - ln (cos^{2} (3 x))

\frac{1}{- 0.0001216} ln (\frac{2}{5})

\frac{3}{8} lo g_{2} (\frac{3}{8}) + \frac{5}{8} lo g_{2} (\frac{5}{8})

ln (x) + ln (7) - ln (2) - 2 ln (4)

- lo g_{10} (5.33 \cdot 1 0^{- 6})

What is ln((2x-5)/(cos^2(3x))) ?
The solution to ln((2x-5)/(cos^2(3x))) is ln(2x-5)-ln(cos^2(3x))