What are the solutions to the equation 3n^2-n=14 ?

The solutions to the equation 3n^2-n=14 are n= 7/3 ,n=-2

Find the zeros of 3n^2-n=14

The zeros of 3n^2-n=14 are n= 7/3 ,n=-2

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3 n^{2} - n = 14

n = \frac{7}{3}, n = - 2

Solution steps

3 n^{2} - n = 14

Move

14

to the left side

3 n^{2} - n - 14 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 14 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 14) = 13

n_{1, 2} = \frac{- ( - 1 ) \pm 13}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- ( - 1 ) + 13}{2 \cdot 3}, n_{2} = \frac{- ( - 1 ) - 13}{2 \cdot 3}

n = \frac{- ( - 1 ) + 13}{2 \cdot 3} : \frac{7}{3}

n = \frac{- ( - 1 ) - 13}{2 \cdot 3} : - 2

The solutions to the quadratic equation are:

n = \frac{7}{3}, n = - 2

2 x - 31 = 3 (x + 2)

- (\frac{2}{3})^{2} + 9 (\frac{2}{3})

- 6 (x - 3) - 26 = - 8

3 (y - 2) + 8 = 14

(10 + 15 i) - (48 - 30 i)

What are the solutions to the equation 3n^2-n=14 ?
The solutions to the equation 3n^2-n=14 are n= 7/3 ,n=-2
Find the zeros of 3n^2-n=14
The zeros of 3n^2-n=14 are n= 7/3 ,n=-2