What is log_{10}((1-x)/(1+x)) ?

The solution to log_{10}((1-x)/(1+x)) is log_{10}(1-x)-log_{10}(1+x)

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simplify log_{10}((1-x)/(1+x))

simplify

lo g_{10} (\frac{1 - x}{1 + x})

lo g_{10} (1 - x) - lo g_{10} (1 + x)

Solution steps

lo g_{10} (\frac{1 - x}{1 + x})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{1 - x}{1 + x}) = lo g_{10} (1 - x) - lo g_{10} (1 + x)

= lo g_{10} (1 - x) - lo g_{10} (1 + x)

lo g_{10} (\frac{x ^{2}}{y z})

lo g_{10} (\frac{x z}{y ^{3}})

2 ln (x) - 3 ln (y) + 5 ln (z)

lo g_{3} (x^{2} + 9 x + 18) - lo g_{3} (x + 3)

\frac{2}{3} lo g_{10} (\frac{5.96 x ^{1016}}{1 0 ^{4.4}})

What is log_{10}((1-x)/(1+x)) ?
The solution to log_{10}((1-x)/(1+x)) is log_{10}(1-x)-log_{10}(1+x)