What is log_{10}(y)-log_{10}(2) ?

The solution to log_{10}(y)-log_{10}(2) is log_{10}(y/2)

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simplify log_{10}(y)-log_{10}(2)

simplify

lo g_{10} (y) - lo g_{10} (2)

lo g_{10} (\frac{y}{2})

Solution steps

lo g_{10} (y) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (y) - lo g_{10} (2) = lo g_{10} (\frac{y}{2})

= lo g_{10} (\frac{y}{2})

- lo g_{10} (2.95 \cdot 1 0^{- 4})

lo g_{10} (\frac{x}{q ( z - 9 ) ^{2}})

lo g_{3} (\frac{27}{x + 8})

ln (x^{2} y^{5} z)

ln (20) - ln (5)

What is log_{10}(y)-log_{10}(2) ?
The solution to log_{10}(y)-log_{10}(2) is log_{10}(y/2)