What is log_{2}(a)-log_{2}(b)-log_{2}(c) ?

The solution to log_{2}(a)-log_{2}(b)-log_{2}(c) is log_{2}(a/(bc))

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simplify log_{2}(a)-log_{2}(b)-log_{2}(c)

simplify

lo g_{2} (a) - lo g_{2} (b) - lo g_{2} (c)

lo g_{2} (\frac{a}{b c})

Solution steps

lo g_{2} (a) - lo g_{2} (b) - lo g_{2} (c)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (a) - lo g_{2} (b) = lo g_{2} (\frac{a}{b})

= lo g_{2} (\frac{a}{b}) - lo g_{2} (c)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{2} (\frac{a}{b}) - lo g_{2} (c) = lo g_{2} (\frac{\frac{a}{b}}{c})

= lo g_{2} (\frac{\frac{a}{b}}{c})

Simplify

\frac{\frac{a}{b}}{c} : \frac{a}{b c}

= lo g_{2} (\frac{a}{b c})

lo g_{10} (x^{5})

lo g_{a} (2) + lo g_{a} (3)

2 ln (2) + 3 ln (x) - 12 ln (x + 5)

lo g_{10} (5 x) - 3

lo g_{35} (\frac{20000}{35}) + 1

What is log_{2}(a)-log_{2}(b)-log_{2}(c) ?
The solution to log_{2}(a)-log_{2}(b)-log_{2}(c) is log_{2}(a/(bc))