What is log_{10}(x+3)-log_{10}(2x) ?

The solution to log_{10}(x+3)-log_{10}(2x) is log_{10}((x+3)/(2x))

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simplify log_{10}(x+3)-log_{10}(2x)

simplify

lo g_{10} (x + 3) - lo g_{10} (2 x)

lo g_{10} (\frac{x + 3}{2 x})

Solution steps

lo g_{10} (x + 3) - lo g_{10} (2 x)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (x + 3) - lo g_{10} (2 x) = lo g_{10} (\frac{x + 3}{2 x})

= lo g_{10} (\frac{x + 3}{2 x})

2 lo g_{10} (5) - \frac{1}{2} lo g_{10} (5)

2 ln (5 x^{2}) - ln (2 x^{2})

ln (\frac{5 x}{y})

- lo g_{10} (1.8 \cdot 1 0^{- 2})

lo g_{b} (9) + lo g_{b} (7)

What is log_{10}(x+3)-log_{10}(2x) ?
The solution to log_{10}(x+3)-log_{10}(2x) is log_{10}((x+3)/(2x))