What is ln(5(10))+e^{-1.31(10)} ?

The solution to ln(5(10))+e^{-1.31(10)} is ln(5)+ln(10)+1/(e^{13.1)}

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simplify ln(5(10))+e^{-1.31(10)}

simplify

ln (5 (10)) + e^{- 1.31 (10)}

ln (5) + ln (10) + \frac{1}{e ^{13.1}}

Decimal Notation

3.91202 \dots

Solution steps

ln (5 (10)) + e^{- 1.31 (10)}

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

ln (5 (10)) = ln (5) + ln (10)

= ln (5) + ln (10) + e^{- (10) \cdot 1.31}

Remove parentheses:

(a) = a

= ln (5) + ln (10) + e^{- 1.31 \cdot 10}

Multiply the numbers:

1.31 \cdot 10 = 13.1

= ln (5) + ln (10) + e^{- 13.1}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

= ln (5) + ln (10) + \frac{1}{e ^{13.1}}

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lo g_{b} (8) - lo g_{b} (4) - 2 lo g_{b} (3)

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lo g_{9} (1 1^{3} \cdot 7^{4})

What is ln(5(10))+e^{-1.31(10)} ?
The solution to ln(5(10))+e^{-1.31(10)} is ln(5)+ln(10)+1/(e^{13.1)}