What are the solutions to the equation 527^2+320^2=x^2 ?

The solutions to the equation 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)

Find the zeros of 527^2+320^2=x^2

The zeros of 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)

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52 7^{2} + 32 0^{2} = x^{2}

x = 380129, x = - 380129

Decimal Notation

x = 616.54602 \dots, x = - 616.54602 \dots

Solution steps

52 7^{2} + 32 0^{2} = x^{2}

Switch sides

x^{2} = 52 7^{2} + 32 0^{2}

Simplify

52 7^{2} + 32 0^{2} : 380129

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 380129, x = - 380129

\frac{10}{3 n - 4} - \frac{5}{4 - 3 n}

x + 5 = 11

\frac{2}{5} - \frac{2}{3}

3 (a - b)^{2} + 5 (a - b) + 2

- 2 x^{2} + 4 x - 2

What are the solutions to the equation 527^2+320^2=x^2 ?
The solutions to the equation 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)
Find the zeros of 527^2+320^2=x^2
The zeros of 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)