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What are the solutions to the equation 527^2+320^2=x^2 ?
The solutions to the equation 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)Find the zeros of 527^2+320^2=x^2
The zeros of 527^2+320^2=x^2 are x=sqrt(380129),x=-sqrt(380129)