What is log_{10}(1/3)+log_{10}(2) ?

The solution to log_{10}(1/3)+log_{10}(2) is log_{10}(2/3)

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simplify log_{10}(1/3)+log_{10}(2)

simplify

lo g_{10} (\frac{1}{3}) + lo g_{10} (2)

lo g_{10} (\frac{2}{3})

Decimal Notation

- 0.17609 \dots

Solution steps

lo g_{10} (\frac{1}{3}) + lo g_{10} (2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (\frac{1}{3}) + lo g_{10} (2) = lo g_{10} (\frac{1}{3} \cdot 2)

= lo g_{10} (\frac{1}{3} \cdot 2)

\frac{1}{3} \cdot 2 = \frac{2}{3}

= lo g_{10} (\frac{2}{3})

- lo g_{10} (1.21 \cdot 1 0^{- 3})

ln ∣ 1 ∣ - \frac{3}{2} ln ∣ 5 ∣ + 2 ln ∣ 6 ∣ + C

ln (x^{9} 5 - x)

lo g_{10} (\frac{8 m}{n})

\frac{10}{ln ( 302 )} - \frac{3000}{151 ln ^{2} ( 302 )} + 3

What is log_{10}(1/3)+log_{10}(2) ?
The solution to log_{10}(1/3)+log_{10}(2) is log_{10}(2/3)