What is 1/2 log_{10}(16)-1/3 log_{10}(8)+1 ?

The solution to 1/2 log_{10}(16)-1/3 log_{10}(8)+1 is log_{10}(2)+1

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simplify 1/2 log_{10}(16)-1/3 log_{10}(8)+1

simplify

\frac{1}{2} lo g_{10} (16) - \frac{1}{3} lo g_{10} (8) + 1

lo g_{10} (2) + 1

Decimal Notation

1.30102 \dots

Solution steps

\frac{1}{2} lo g_{10} (16) - \frac{1}{3} lo g_{10} (8) + 1

\frac{1}{2} lo g_{10} (16) = 2 lo g_{10} (2)

\frac{1}{3} lo g_{10} (8) = lo g_{10} (2)

= 2 lo g_{10} (2) - lo g_{10} (2) + 1

Add similar elements:

2 lo g_{10} (2) - lo g_{10} (2) = lo g_{10} (2)

= lo g_{10} (2) + 1

lo g_{2} (x) + 2 + lo g_{2} (x^{3}) - 4

lo g_{5} (5 x)

lo g_{10} (\frac{x ^{2}}{z y})

lo g_{10} (5 x^{4})

2 lo g_{10} (x) - lo g_{10} (11)

What is 1/2 log_{10}(16)-1/3 log_{10}(8)+1 ?
The solution to 1/2 log_{10}(16)-1/3 log_{10}(8)+1 is log_{10}(2)+1