What is log_{5}(x)-log_{5}(x+2) ?

The solution to log_{5}(x)-log_{5}(x+2) is log_{5}(x/(x+2))

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simplify log_{5}(x)-log_{5}(x+2)

simplify

lo g_{5} (x) - lo g_{5} (x + 2)

lo g_{5} (\frac{x}{x + 2})

Solution steps

lo g_{5} (x) - lo g_{5} (x + 2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{5} (x) - lo g_{5} (x + 2) = lo g_{5} (\frac{x}{x + 2})

= lo g_{5} (\frac{x}{x + 2})

lo g_{t} (8 Y)

ln (\frac{71}{2})

2 ln (2) - \frac{1}{2} ln (x^{3} + 5 x)

\frac{lo g _{10} ( x ) + lo g _{10} ( 3 x ^{2} )}{2}

- 0.375 \cdot lo g_{2} (0.375) - 0.625 \cdot lo g_{2} (0.625)

What is log_{5}(x)-log_{5}(x+2) ?
The solution to log_{5}(x)-log_{5}(x+2) is log_{5}(x/(x+2))