What is log_{10}((x+2)/(x-1)) ?

The solution to log_{10}((x+2)/(x-1)) is log_{10}(x+2)-log_{10}(x-1)

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simplify log_{10}((x+2)/(x-1))

simplify

lo g_{10} (\frac{x + 2}{x - 1})

lo g_{10} (x + 2) - lo g_{10} (x - 1)

Solution steps

lo g_{10} (\frac{x + 2}{x - 1})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{x + 2}{x - 1}) = lo g_{10} (x + 2) - lo g_{10} (x - 1)

= lo g_{10} (x + 2) - lo g_{10} (x - 1)

- \frac{7}{10} lo g_{2} (\frac{7}{10}) - \frac{3}{10} lo g_{2} (\frac{3}{10})

ln (\frac{x}{( π + 1 ) p}) + π ln (\frac{π x}{( π + 1 ) o})

lo g_{7} (t^{9})

ln (\frac{25}{6})

What is log_{10}((x+2)/(x-1)) ?
The solution to log_{10}((x+2)/(x-1)) is log_{10}(x+2)-log_{10}(x-1)