What is log_{10}(28)-log_{10}(14) ?

The solution to log_{10}(28)-log_{10}(14) is log_{10}(2)

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simplify log_{10}(28)-log_{10}(14)

simplify

lo g_{10} (28) - lo g_{10} (14)

lo g_{10} (2)

Decimal Notation

0.30102 \dots

Solution steps

lo g_{10} (28) - lo g_{10} (14)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (28) - lo g_{10} (14) = lo g_{10} (\frac{28}{14})

= lo g_{10} (\frac{28}{14})

Divide the numbers:

\frac{28}{14} = 2

= lo g_{10} (2)

6 lo g_{10} (5) - lo g_{10} (2) - 3 lo g_{10} (3)

lo g_{4} (p^{2}) - lo g_{4} (4 q)

ln (34) ln (17)

2 lo g_{3} (3 x) - lo g_{3} (2 x) + lo g_{3} (x^{2} + 1)

lo g_{10} (x^{2} + 3 x + 2) - lo g_{10} (x^{2} - 4)

What is log_{10}(28)-log_{10}(14) ?
The solution to log_{10}(28)-log_{10}(14) is log_{10}(2)