What is log_{4}(7)-log_{4}(8/5) ?

The solution to log_{4}(7)-log_{4}(8/5) is log_{4}(35/8)

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simplify log_{4}(7)-log_{4}(8/5)

simplify

lo g_{4} (7) - lo g_{4} (\frac{8}{5})

lo g_{4} (\frac{35}{8})

Decimal Notation

1.06464 \dots

Solution steps

lo g_{4} (7) - lo g_{4} (\frac{8}{5})

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{4} (7) - lo g_{4} (\frac{8}{5}) = lo g_{4} (\frac{7}{\frac{8}{5}})

= lo g_{4} (\frac{7}{\frac{8}{5}})

\frac{7}{\frac{8}{5}} = \frac{35}{8}

= lo g_{4} (\frac{35}{8})

ln (7 e^{7 x})

lo g_{10} (x^{2}) (x + 4)

lo g_{10} (\frac{x ( x + 3 )}{( x + 5 ) ^{9}})

e^{\frac{l n ( 3 ) - l n ( 8 ) + l n ( 25 ) - l n ( 6 )}{2}}

lo g_{10} (\frac{5 x + 7}{2})

What is log_{4}(7)-log_{4}(8/5) ?
The solution to log_{4}(7)-log_{4}(8/5) is log_{4}(35/8)