What is 2log_{10}(x)+log_{10}(x-4) ?

The solution to 2log_{10}(x)+log_{10}(x-4) is log_{10}(x^2(x-4))

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simplify 2log_{10}(x)+log_{10}(x-4)

simplify

2 lo g_{10} (x) + lo g_{10} (x - 4)

lo g_{10} (x^{2} (x - 4))

Solution steps

2 lo g_{10} (x) + lo g_{10} (x - 4)

Apply log rule:

a lo g_{c} (b) = lo g_{c} (b^{a})

2 lo g_{10} (x) = lo g_{10} (x^{2})

= lo g_{10} (x^{2}) + lo g_{10} (x - 4)

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{10} (x^{2}) + lo g_{10} (x - 4) = lo g_{10} (x^{2} (x - 4))

= lo g_{10} (x^{2} (x - 4))

14 + lo g_{10} (1.61 \cdot 1 0^{- 14})

98.92 - 10 lo g_{10} (\frac{0.00678}{1 \cdot 1 0 ^{- 12}})

ln (\frac{25}{2})

lo g_{10} (\frac{4}{ab})

ln ((sin (x))^{l n (x)})

What is 2log_{10}(x)+log_{10}(x-4) ?
The solution to 2log_{10}(x)+log_{10}(x-4) is log_{10}(x^2(x-4))