What is log_{10}((p^6)/(q^1)) ?

The solution to log_{10}((p^6)/(q^1)) is 6log_{10}(p)-log_{10}(q)

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simplify log_{10}((p^6)/(q^1))

simplify

lo g_{10} (\frac{p ^{6}}{q ^{1}})

6 lo g_{10} (p) - lo g_{10} (q)

Solution steps

lo g_{10} (\frac{p ^{6}}{q ^{1}})

Simplify

\frac{p ^{6}}{q ^{1}} : \frac{p ^{6}}{q}

= lo g_{10} (\frac{p ^{6}}{q})

Apply log rule:

lo g_{a} (\frac{x}{y}) = lo g_{a} (x) - lo g_{a} (y)

lo g_{10} (\frac{p ^{6}}{q}) = lo g_{10} (p^{6}) - lo g_{10} (q)

= lo g_{10} (p^{6}) - lo g_{10} (q)

Simplify

lo g_{10} (p^{6}) : 6 lo g_{10} (p)

= 6 lo g_{10} (p) - lo g_{10} (q)

lo g_{10} (12 x^{2})

20 lo g_{10} (\frac{4 π}{\frac{1}{8}}) - 20 lo g_{10} (0.5)

- (\frac{3}{8} lo g_{2} (\frac{3}{8}) + \frac{5}{8} lo g_{2} (\frac{5}{8}))

5 lo g_{7} (2 x) - \frac{1}{3} lo g_{7} (5 x - 1)

ln (θ e^{θ} x^{- θ - 1})

What is log_{10}((p^6)/(q^1)) ?
The solution to log_{10}((p^6)/(q^1)) is 6log_{10}(p)-log_{10}(q)