What is log_{n}(a)-log_{n}(a-n) ?

The solution to log_{n}(a)-log_{n}(a-n) is log_{n}(a/(a-n))

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simplify log_{n}(a)-log_{n}(a-n)

simplify

lo g_{n} (a) - lo g_{n} (a - n)

lo g_{n} (\frac{a}{a - n})

Solution steps

lo g_{n} (a) - lo g_{n} (a - n)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{n} (a) - lo g_{n} (a - n) = lo g_{n} (\frac{a}{a - n})

= lo g_{n} (\frac{a}{a - n})

ln (2) + ln (4) + ln (6)

lo g_{\frac{1}{3}} (21) + lo g_{3} (14) - lo g_{3} (18)

ln (\frac{0.000408}{0.000231})

ln (2 e^{5 x})

\frac{d}{d x} (ln (4 x - 3)) + ln (2 x)

What is log_{n}(a)-log_{n}(a-n) ?
The solution to log_{n}(a)-log_{n}(a-n) is log_{n}(a/(a-n))