What is log_{10}(24)-log_{10}(2) ?

The solution to log_{10}(24)-log_{10}(2) is log_{10}(12)

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simplify log_{10}(24)-log_{10}(2)

simplify

lo g_{10} (24) - lo g_{10} (2)

lo g_{10} (12)

Decimal Notation

1.07918 \dots

Solution steps

lo g_{10} (24) - lo g_{10} (2)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (24) - lo g_{10} (2) = lo g_{10} (\frac{24}{2})

= lo g_{10} (\frac{24}{2})

Divide the numbers:

\frac{24}{2} = 12

= lo g_{10} (12)

lo g_{10} (\frac{2.51 \cdot 1 0 ^{- 9}}{x})

- lo g_{10} (4.34 \cdot 1 0^{- 6})

2 lo g_{10} (y^{3}) + lo g_{10} (y^{2})

lo g_{a} (x^{2}) - 2 lo g_{a} (x)

4 lo g_{3} (x^{2} - 1) - 2 lo g_{3} (x + 1)

What is log_{10}(24)-log_{10}(2) ?
The solution to log_{10}(24)-log_{10}(2) is log_{10}(12)